**Logarithms and the Richter Scale**

**Overview:**

Quantifying the magnitude of earthquakes is an application of logarithms. Earthquake intensity can vary significantly so the logarithm of intensity is used to compare magnitude of differing intensities.

Richter scale magnitude is the base ten logarithm of earthquake intensity divided by a standard intensity

The basic equation of magnitude and intensity is:

M = log (I/S), where:

• M is the magnitude of an earth quake

• I is the intensity of the earthquake measured by the amplitude of a wave form on a seismograph reading taken 100 km from the epicenter.

• S is the intensity of a “standard” (and very weak) earthquake, whose amplitude on a seismograph is one micron, or 10^-4 cm.

**About magnitude and intensity**

With the Richter scale, earthquake magnitude is a computed value based on an empirical measured value, which is the intensity of an earthquake. Intensity is the wave height on a seismograph that records earth movement during an earthquake.

The Richter scale is a scale of magnitude values. The seismograph reports intensity. Intensity is the amplitude of a graph on a seismometer that records ground movement during an earthquake. Intensity is a measured quantity that is recorded by an instrument. Magnitude by comparison is a computed value.

**More about the equations**

The basic equation for magnitude and intensity is

M = log (I/S) or magnitude is the base ten logarithm of intensity over standard.

Applying some algebra and rules of logarithms, Intensity can be isolated

M = log (I/S)

10^M = 10^(Log(I/S))

10^M = I/S

I = (10^M) * S

If M = log(I/S) and I = S then M = log (I/S) = log (1) = 0 because 10^0 = 1. This means that the magnitude of a ‘small’ earthquake is 0 on the Richter scale

**Richter scale problems**

- Given the intensity of an earthquake then calculate magnitude
- Given the magnitude of an earthquake calculate the intensity.
- If one earthquake is nx the intensity of another then how much greater is the magnitude on the Richter scale?
- Given two earthquakes of different magnitude on the Richter scale how many more times intense was the quake of greater magnitude
- Given the magnitude of an earthquake, such as the SFO 1906 earthquake was magnitude 8.3, and some other earthquake had Xn the intensity then what is the magnitude of that second earthquake?
- Given the magnitude of one earthquake, and that the intensity of a second earthquake is Xn the first, what is the magnitude of the second earthquake

If the intensity of an earthquake is given then the magnitude can be computed.

If the magnitude of an earthquake is given then the intensity can be computed.

One unknown can be solved with one equation, and two unknowns can be solved with two equations

**Conversion:**

The most important equation to know is that magnitude is the base ten logarithm of intensity, and that intensity is the wave height on a seismograph recording movement. The expression is:

M = Log(I/S)

Using algebra and rules of logarithms, Intensity can be isolated and expressed in terms of magnitude.

10^M = 10^(Log(I/S))

10^M = I/S

If I=80,500,000 and S=1 then M=Log(80,500,000) = 7.9

If I=48,275,000 and S=1 then M=Log(48,275,000) = 7.7

If I=251,200 and S=1 then M=Log(251,200) = 5.4

If M = 8.6 then I = 10^8.6 = 398,107,171

If M = 6.7 then I = 10^6.7 = 5,011,872

If M = 7.7 then I = 10^7.7 = 50,118,723

**Example**

If one earthquake is 20x the intensity of another, how much larger is the magnitude on the Richter scale?

M = log(I/S) = log(20I2/I2) = log(20) = 1.3

**Example**

SFO earthquake in 1906 was magnitude 8.3 on the Richter scale

Loma Prieta earthquake in 1989 was magnitude 7.1 on the Richter scale

How many more times intense was the 1906 earthquake?

8.3 = log(I1/s) and 7.1 = log(I2/S)

This works if S = 1.

Objective is to compute log((I2/S)/(I1/S)) = log(I2/I1) =

log(I2) - log(I1/S) = 8.3 - 7.1 = 1.2

log(I2/I1) = 1.2 exponentiate both sides

10^(I2/I1) = 10^1.2

I2/I1 = 10^1.2 = 15.8

Intensity is 15.8x

**Example**

SFO 1906 magnitude = 8.3, Japan 1906 = magnitude 4.9

How many times more intense was SFO 1906?

Magnitude is the base 10 log of intensity divided by a constant S. M = log(I/S). Assume S = 1 (It is actually 10^-4)

1). 8.3 = log(I1/S) and

2). 4.9 = log(I2/S)

Objective is to compute I1/I2

Subtract 2 from 1:

8.3 - 4.9 = log(I1/S) - log(I2/S) = log((I1/S)/(I2/S)) = Log(I1/I2)

3.4 = log(I1/I2)

10^3.4 = 10^(log(I1/I2)) = I1/I2 = 2,511

**Example**

Northridge 1994 magnitude 6.8. Call this M1

Kobe 1995 magnitude 7.2. Call this M2

How many times more intense was Kobe? In other words find I2/I1.

Remember: M = log(I/S).

M2 = 7.2 = log(I2/S)

M1 = 6.8 = log(I1/S)

Subtract M2 from M1:

7.2 - 6.8 = log(I2/S) - log(I1/S) = log((I2/S)/(I1/S)) = log(I2/I1) = 0.4

0.4 = log(I2/I1) Exponentiate both sides

10^0.4 = 10^(log(I2/I1))

10^0.4 = 2.51

10^(log(I2/I1)) = I2/I1

I2/I1 = 2.51

Kobe was 2.51x intense

**Example**

Alaska 1964 magnitude 8.6. Call this M1

SFO 1906 magnitude 8.3. Call this M2

How many times more intense was Alaska 1964?

M1 = Log(I1/S)

8.6 = Log(I1/S)

M2 = Log(I2/S)

8.3 = Log(I2/S)

Subtract M1 from M2:

8.6 - 8.3 = Log(I1/S) - Log(I2/S)

0.3 = Log(I1/I2)

10^0.3 = 10^(Log(I1/I2))

1.995 = I1/I2

Alaska 1964 was about 2x more intense

**Example**

If magnitude 1 is 7.3 and magnitude 2 is 4.8 what is the ratio of I1/I2?

7.3 = Log(I1/S)

4.8 = Log(I2/S)

Subtract M2 from M1:

7.3 - 4.8 = Log(I1/S) - Log(I2/S) = Log(I1/I2)

2.5 = Log(I1/I2) Exponentiate both sides

10^2.5 = 10^(Log(I1/I2)) = I1/I2

10^2.5 = 316.2

I1/I2 = 316.2

**Example**

The SFO earthquake in 1906 was of an estimated 8.3 magnitude on the Richter scale.

The Colombia-Ecuador earthquake had 4 times the intensity.

What is the magnitude of the Colombia earthquake?

SFO: M = Log(I/S) = 8.3

Colombia:

M = Log(4I/S) = Log(4) + Log(I/S) note that Log(I/S)=8.3

M= Log(4) + 8.3 Base ten log of 4 = 0.602

M = 0.602 + 8.3 ~=8.9

Colombia earth quake was magnitude 8.9

**Example**

M1: Landers earthquake was magnitude 7.3

M2: Northridge in 1994 was magnitude 6.7

How many times more powerful (intense, I) was Landers

M1 = Log(I1/S) = 7.3

7.3 = Log(I1/S)

10^7.3 = 10^(Log(I1/S)) Exponentiate both sides

10^7.3 = I/S Simplify

M2 = Log(I2/S) = 6.7

6.7 = Log(I2/S)

10^6.7 = 10^(Log(I2/S)) Exponentiate both sides

10^6.7 = Log(I2/S)

Divide M1 by M2:

10^7.3 / 10^6.7 = (I1/S) / (I2/S) = I1/I2

10^(7.3) - 10^(6.7) = 10^(7.3 - 6.7) = 10^(0.6) = 3.98

I1/I2 = 3.98 meaning Landers was 3.98x intense

**Example**

If an earthquake had magnitude 6.5 then compute the magnitude of an earthquake that had 35x the intensity

M1 = 6.5 = Log(I/S) M2 = Log(35I/S)

6.5 = Log(I/S)

10^6.5 = 10^(Log(I/S))

10^6.5 = I/S

I = 10^6.5/S

M2 = Log(35I/S)

M2 = Log(35*10^6.5/S/S)

M2 = Log(35*10^6.5)

M2 ~= 8.04

Magnitude of earthquake 35 times the intensity of a magnitude 6.5 earthquake is 8.0

**Example**

M1 = 1985 earthquake in Mexico of magnitude 8.1

M2 = 1976 earthquake in China of 1.26x intensity.

Compute the magnitude of M2

M1 = Log(I1/S) M2 = Log(1.26I/S)

8.1 = Log(I1/S)

Subtract M1 from M2:

M2 - M1 = Log(1.26I1/S) - Log(I/S)

M2 - 8.1 = Log((1.26I/S) / (I/S)) Simplify

M2 - 8.1 = Log(1.26)

M2 = Log(1.26) + 8.1 Log(1.26) ~=0.1

M2 ~= 8.2

Summarize this: Compare magnitude and intensity differences